WebFeb 1, 2024 · As the answer may grow large, the answer must be computed modulo 10^9 + 7. Example 1: Input: arr = [1,3,5] ... List [int])-> int: MOD = int (1e9) + 7 counter = [0] * 2 s = ans = 0 for v in arr: s += v counter [s % 2] += 1 if s % 2 == 1: ans += 1 + counter [0] else: ans += counter [1] return ans % MOD. WebMar 1, 2024 · Compute a = a % mod. While b > 0, perform the following operations: If b % 2 == 1, add a to res modulo mod. Multiply a by 2 and compute a = a % mod. Divide b by …
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Webpublic static final int MOD = (int) 1e9 + 7; public static void main ( String args [ ] ) throws IOException { BufferedReader r = new BufferedReader ( new InputStreamReader ( System . in ) ) ; WebSep 2, 2024 · Even though the area of the board game can be large (up to 190), the smaller side of the board will be much smaller. Without loss of generality, assuming that R <= C (if R > C, just swapping them and the answer will not change). R * C <= 190 implies R <= sqrt (190) = 13. There will be at most 13 cells in each column. rsno at the movies
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WebJun 22, 2024 · project euler 759 2024-06-22. Word count: 1.3k Reading time≈ 7 min WebNov 2, 2015 · For large k, we can reduce the work significantly by exploiting two fundamental facts:. If p is a prime, the exponent of p in the prime factorisation of n! is … WebJan 10, 2024 · If the current dist value is the same as the previously stored dist value at the same index, increment the number of ways by 1 at that index. We repeat the above steps until the queue becomes empty or till we reach the destination. Return the ways [n-1] modulo 10^9+7 when the queue becomes empty. Here’s a quick demonstration of the … rsno christmas